

Half an hour later, Tina left Riverside in her car on the same route as Stephanie, driving 70 miles per hour. Stephanie left Riverside, California, driving her motorhome north on Interstate 15 towards Salt Lake City at a speed of 56 miles per hour. How many stoves would Mitchell need to sell for the options to be equal?

#Solve by substitution plus#
Company B offers him a position with a salary of $24,000 plus a $50 commission for each stove he sells.

My y quantity I hope is equal to 2 times my x quantity take away 3.

I also need to check it into the second equation. Good so I’m half way there, I think it's right. So here comes my check, first I’m going to check it in the first equation, is it true that my y quantity is equal to 3 times my x quantity plus 1? Let’s see -11 equals -12 plus 1, yap that’s true. In order to check my work, I’m going to go back and plug in -4 for x and -11 to y into both original equations and make sure I get equalities. I’m pretty sure that’s my answer, I’m pretty sure that’s the point where these lines cross even though I didn’t graph them. Y is equal to 3 times my x quantity plus 1, so y is equal to -11 oops, that’s a +1 right there, plus 1 okay. I could also use the second one and I’ll still get the same answer for y. I’m just going to choose to use the first equation. In order to find y, I’m going to take x equals -4, and substitute it into either original equation, that way I’ll get my y value, and I’ll go back and check in a second. I’m going to put a box around this like I would have with my whole answer keeping in mind I still need to find what that y value is. Keep in mind that’s only going to be half of my answer. Now I need to get x all by itself by subtracting 1 from both sides, x is equal to -4. Here we go if I want to find x, I’m going to subtract 2 Xs from both sides, so now I have x plus 1 equals -3. I’m going to find x, and then go back and find my y value. Now this is a straight forward solving problem. Just as when solving integrals, one method to try is to change variables to end up with a simpler equation to solve. That guy is equal to y and that guy is also equal to y, so I’m just substituting those two equations so they look like one equation with one variable. Since I know y is equal to the expression 3x plus 1, and y is also equal to the expression 2x minus 3, it makes sense mathematically to write 3x plus 1 equals 2x minus 3. This problem using substitution is going to be not too difficult because I have 2 equations that are both already solved for y.
